case test.cons
n m h_n h_i : ℕ,
h_is : list ℕ,
h_a : test h_n h_is,
h : test (nat.succ (nat.add h_n (nat.add 2 0))) (h_i :: h_is)
⊢ n + n = nat.succ (nat.add h_n (nat.add 2 0)) → [m] = h_i :: h_is → false
1794.lean:8:0: warning: declaration 'example3' uses sorry
