test: let rec in tactic mode

@Kha: I added support for using `let rec` in tactic mode.
This commit is contained in:
Leonardo de Moura 2020-10-30 14:47:09 -07:00
parent f2530e069a
commit 060535679f

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@ -0,0 +1,87 @@
import Lean
inductive Tree
| leaf : Tree
| node : Tree → Tree → Tree
abbrev notLtX (x : Tree) (t : Tree) : Prop :=
Tree.ibelow (motive := fun z => x ≠ z) t
theorem Tree.acyclic (x t : Tree) : x = t → notLtX x t := by
let rec right (x s : Tree) (b : Tree) (h : notLtX x b) : node s x ≠ b ∧ notLtX (node s x) b := by
match b, h with
| leaf, h =>
apply And.intro _ trivial
intro h; injection h
| node l r, h =>
have ihl : notLtX x l → node s x ≠ l ∧ notLtX (node s x) l from right x s l
have ihr : notLtX x r → node s x ≠ r ∧ notLtX (node s x) r from right x s r
have hl : x ≠ l ∧ notLtX x l from h.1
have hr : x ≠ r ∧ notLtX x r from h.2.1
have ihl : node s x ≠ l ∧ notLtX (node s x) l from ihl hl.2
have ihr : node s x ≠ r ∧ notLtX (node s x) r from ihr hr.2
apply And.intro
focus
intro h
injection h with _ h
exact absurd h hr.1
done
focus
apply And.intro
apply ihl
apply And.intro _ trivial
apply ihr
let rec left (x t : Tree) (b : Tree) (h : notLtX x b) : node x t ≠ b ∧ notLtX (node x t) b := by
match b, h with
| leaf, h =>
apply And.intro _ trivial
intro h; injection h
| node l r, h =>
have ihl : notLtX x l → node x t ≠ l ∧ notLtX (node x t) l from left x t l
have ihr : notLtX x r → node x t ≠ r ∧ notLtX (node x t) r from left x t r
have hl : x ≠ l ∧ notLtX x l from h.1
have hr : x ≠ r ∧ notLtX x r from h.2.1
have ihl : node x t ≠ l ∧ notLtX (node x t) l from ihl hl.2
have ihr : node x t ≠ r ∧ notLtX (node x t) r from ihr hr.2
apply And.intro
focus
intro h
injection h with h _
exact absurd h hl.1
done
focus
apply And.intro
apply ihl
apply And.intro _ trivial
apply ihr
let rec aux : (x : Tree) → notLtX x x
| leaf => trivial
| node l r => by
have ih₁ : notLtX l l from aux l
have ih₂ : notLtX r r from aux r
show (node l r ≠ l ∧ notLtX (node l r) l) ∧ (node l r ≠ r ∧ notLtX (node l r) r) ∧ True
apply And.intro
focus
apply left
assumption
apply And.intro _ trivial
focus
apply right
assumption
intro h
subst h
apply aux
open Tree
theorem ex1 (x : Tree) : x ≠ node leaf (node x leaf) := by
intro h
exact absurd rfl $ Tree.acyclic _ _ h $.2.1.2.1.1
theorem ex2 (x : Tree) : x ≠ node x leaf := by
intro h
exact absurd rfl $ Tree.acyclic _ _ h $.1.1
theorem ex3 (x y : Tree) : x ≠ node y x := by
intro h
exact absurd rfl $ Tree.acyclic _ _ h $.2.1.1