chore: upstream String.dropPrefix? (#5728)
Useful String helper functions widely used in tactic implementations.
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@ -317,6 +317,9 @@ theorem _root_.Char.utf8Size_le_four (c : Char) : c.utf8Size ≤ 4 := by
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@[simp] theorem pos_add_char (p : Pos) (c : Char) : (p + c).byteIdx = p.byteIdx + c.utf8Size := rfl
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protected theorem Pos.ne_zero_of_lt : {a b : Pos} → a < b → b ≠ 0
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| _, _, hlt, rfl => Nat.not_lt_zero _ hlt
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theorem lt_next (s : String) (i : Pos) : i.1 < (s.next i).1 :=
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Nat.add_lt_add_left (Char.utf8Size_pos _) _
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@ -1021,6 +1024,66 @@ instance hasBeq : BEq Substring := ⟨beq⟩
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def sameAs (ss1 ss2 : Substring) : Bool :=
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ss1.startPos == ss2.startPos && ss1 == ss2
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/--
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Returns the longest common prefix of two substrings.
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The returned substring will use the same underlying string as `s`.
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-/
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def commonPrefix (s t : Substring) : Substring :=
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{ s with stopPos := loop s.startPos t.startPos }
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where
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/-- Returns the ending position of the common prefix, working up from `spos, tpos`. -/
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loop spos tpos :=
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if h : spos < s.stopPos ∧ tpos < t.stopPos then
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if s.str.get spos == t.str.get tpos then
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have := Nat.sub_lt_sub_left h.1 (s.str.lt_next spos)
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loop (s.str.next spos) (t.str.next tpos)
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else
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spos
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else
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spos
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termination_by s.stopPos.byteIdx - spos.byteIdx
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/--
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Returns the longest common suffix of two substrings.
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The returned substring will use the same underlying string as `s`.
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-/
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def commonSuffix (s t : Substring) : Substring :=
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{ s with startPos := loop s.stopPos t.stopPos }
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where
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/-- Returns the starting position of the common prefix, working down from `spos, tpos`. -/
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loop spos tpos :=
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if h : s.startPos < spos ∧ t.startPos < tpos then
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let spos' := s.str.prev spos
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let tpos' := t.str.prev tpos
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if s.str.get spos' == t.str.get tpos' then
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have : spos' < spos := s.str.prev_lt_of_pos spos (String.Pos.ne_zero_of_lt h.1)
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loop spos' tpos'
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else
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spos
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else
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spos
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termination_by spos.byteIdx
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/--
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If `pre` is a prefix of `s`, i.e. `s = pre ++ t`, returns the remainder `t`.
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-/
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def dropPrefix? (s : Substring) (pre : Substring) : Option Substring :=
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let t := s.commonPrefix pre
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if t.bsize = pre.bsize then
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some { s with startPos := t.stopPos }
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else
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none
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/--
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If `suff` is a suffix of `s`, i.e. `s = t ++ suff`, returns the remainder `t`.
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-/
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def dropSuffix? (s : Substring) (suff : Substring) : Option Substring :=
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let t := s.commonSuffix suff
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if t.bsize = suff.bsize then
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some { s with stopPos := t.startPos }
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else
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none
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end Substring
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namespace String
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@ -1082,6 +1145,28 @@ namespace String
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@[inline] def decapitalize (s : String) :=
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s.set 0 <| s.get 0 |>.toLower
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/--
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If `pre` is a prefix of `s`, i.e. `s = pre ++ t`, returns the remainder `t`.
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-/
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def dropPrefix? (s : String) (pre : Substring) : Option Substring :=
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s.toSubstring.dropPrefix? pre
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/--
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If `suff` is a suffix of `s`, i.e. `s = t ++ suff`, returns the remainder `t`.
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-/
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def dropSuffix? (s : String) (suff : Substring) : Option Substring :=
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s.toSubstring.dropSuffix? suff
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/-- `s.stripPrefix pre` will remove `pre` from the beginning of `s` if it occurs there,
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or otherwise return `s`. -/
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def stripPrefix (s : String) (pre : Substring) : String :=
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s.dropPrefix? pre |>.map Substring.toString |>.getD s
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/-- `s.stripSuffix suff` will remove `suff` from the end of `s` if it occurs there,
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or otherwise return `s`. -/
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def stripSuffix (s : String) (suff : Substring) : String :=
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s.dropSuffix? suff |>.map Substring.toString |>.getD s
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end String
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namespace Char
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