In the course of the development, I grabbed facts about right shifting
over integers [from
`mathlib4`](https://github.com/leanprover-community/mathlib4/blob/master/Mathlib/Data/Int/Bitwise.lean).
The core proof strategy is to perform a case analysis of the msb:
- If `msb = false`, then `sshiftRight = ushiftRight`.
- If `msb = true`. then `x >>>s i = ~~~(~~~(x >>>u i))`. The double
negation introduces the high `1` bits that one expects of the arithmetic
shift.
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Co-authored-by: Kim Morrison <scott@tqft.net>
