There was a typo in the proof generation. The weird part is that the
proof was valid, but it was very inefficient to check.
The proof was valid because ((n:int) ≥ m) reduces to true/false if n and
m are integer numerals. Thus, if ((n:int) ≥ m) holds then `trivial` is a
valid proof.
However, the reduction is extremely inefficient since it relies on
computations in unary.
In the buggy version, we provided a proof for (a >= 0) where (b >= 0)
was expected. However, both types are definitionally equal to true.
This is why the proof worked.
