closes#1675
After this commit, the following example works as expected.
```
example (p : nat → Prop) (a b : nat) : a = 0 ∧ b = 0 → p (a + b) → p 0 :=
begin
intros h₁ h₂,
simp [h₁] at *,
/- produces the state
(p : nat → Prop) (a b : nat)
h₁ : true
h₂ : p 0
|- p 0
-/
assumption
end
```
as expected.
Remark: the original issue raised by issue #1675 is actually solved by the
`simp_all` tactic.
It now performs self simplification, and the performance is slightly
better. As described at issue #1675, only non dependent propositions
are considered.
@Armael: this tactic may be useful for you
