ea6eee516b
Motivation: use same separator used in lambda expressions as in other programming languages.
38 lines
1.2 KiB
Text
38 lines
1.2 KiB
Text
/-
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Copyright (c) 2019 Microsoft Corporation. All rights reserved.
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Released under Apache 2.0 license as described in the file LICENSE.
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Authors: Leonardo de Moura
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-/
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prelude
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import init.lean.attributes
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namespace Lean
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private def isValidCppId (id : String) : Bool :=
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let first := id.get 0;
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first.isAlpha && (id.toSubstring.drop 1).all (fun c => c.isAlpha || c.isDigit || c == '_')
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private def isValidCppName : Name → Bool
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| (Name.mkString Name.anonymous s) := isValidCppId s
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| (Name.mkString p s) := isValidCppId s && isValidCppName p
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| _ := false
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def mkExportAttr : IO (ParametricAttribute Name) :=
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registerParametricAttribute `export "name to be used by code generators" $ fun _ _ stx =>
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match attrParamSyntaxToIdentifier stx with
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| some exportName =>
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if isValidCppName exportName then Except.ok exportName
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else Except.error "invalid 'export' function name, is not a valid C++ identifier"
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| _ => Except.error "unexpected kind of argument"
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@[init mkExportAttr]
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constant exportAttr : ParametricAttribute Name := default _
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@[export lean.get_export_name_for_core]
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def getExportNameFor (env : Environment) (n : Name) : Option Name :=
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exportAttr.getParam env n
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def isExport (env : Environment) (n : Name) : Bool :=
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(getExportNameFor env n).isSome
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end Lean
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