4 lines
162 B
Text
4 lines
162 B
Text
∀ (y x : Nat), x + (x + y) = x
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∀ (y x : Nat), x + (x + y) = x
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∀ {y x : Nat}, x = y → x + (x + y) = x
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fun (y x : Nat) (h : x = y) (z : Nat) => z + (x + y)
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