3a457e6ad6
Many of our tests in `tests/lean/run/` produce output from `#eval` (or `#check`) statements, that is then ignored. This PR tries to capture all the useful output using `#guard_msgs`. I've only done a cursory check that the output is still sane --- there is a chance that some "unchecked" tests have already accumulated regressions and this just cements them! In the other direction, I did identify two rotten tests: * a minor one in `setStructInstNotation.lean`, where a comment says `Set Nat`, but `#check` actually prints `?_`. Weird? * `CompilerProbe.lean` is generating empty output, apparently indicating that something is broken, but I don't know the signficance of this file. In any case, I'll ask about these elsewhere. (This started by noticing that a recent `grind` test file had an untested `trace_state`, and then got carried away.)
29 lines
1 KiB
Text
29 lines
1 KiB
Text
import Lean
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def explode (x : Nat) : IO Unit := do
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if x == 0 then IO.println "arg is 0"
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if x == 1 then IO.println "arg is 1"
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if x == 2 then IO.println "arg is 2"
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if x == 3 then IO.println "arg is 3"
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if x == 4 then IO.println "arg is 4"
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if x == 5 then IO.println "arg is 5"
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if x == 6 then IO.println "arg is 6"
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if x == 7 then IO.println "arg is 7"
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if x == 8 then IO.println "arg is 8"
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if x == 9 then IO.println "arg is 9"
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if x == 10 then IO.println "arg is 10"
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if x == 11 then IO.println "arg is 11"
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if x == 12 then IO.println "arg is 12"
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if x == 13 then IO.println "arg is 13"
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if x == 14 then IO.println "arg is 14"
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if x == 15 then IO.println "arg is 15"
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if x == 16 then IO.println "arg is 16"
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if x == 17 then IO.println "arg is 17"
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if x == 18 then IO.println "arg is 18"
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if x == 19 then IO.println "arg is 19"
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if x == 20 then IO.println "arg is 20"
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run_meta Lean.Compiler.compile #[``explode]
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set_option trace.Compiler.result true
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run_meta Lean.Compiler.compile #[``explode]
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