lean4-htt/tests/lean/run/2186.lean
Kyle Miller 13036655e9
fix: reduce types when constructing default values in structure instance notation (#5844)
A step of expanding structure instances is to determine all the default
values, and part of this is reducing projections that appear in the
default values so that they get replaced with the user-provided values.
Binder types in foralls, lambdas, and lets have to be reduced too.

Closes #2186
2024-10-26 00:45:21 +00:00

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/-!
# Regression tests for #2186
https://github.com/leanprover/lean4/issues/2186
-/
/-!
Minimization of the issue. The default value to `bar` wasn't working
because the default value of `bar` was `fun (_ : p) => trivial`,
and `p` (which in the default value itself appears as a projection) wasn't being reduced.
-/
namespace Test1
structure A (α : Type u) where
p : Prop
bar : p → True
structure B (α : Type _) extends A α where
bar _ := trivial
-- Previously this needed `bar` to be specified
example : B α where
p := False
end Test1
/-!
Tests from the issue.
-/
namespace Test2
variable (α : Type _)
-- First example
structure A extends LE α where
foo : True
structure B extends LE α where
bar : ∀ a b : α, a ≤ b → True
structure C extends A α, B α
structure D extends C α where
foo := trivial
structure E extends C α where
bar _ _ _ := trivial
-- Always worked
example : D α where
le := Eq
bar _ _ _ := trivial
-- Didn't work
example : E α where
le := Eq
foo := trivial
-- Second example
structure X where
transform : αα
structure A₁ extends X α where
foo : True
structure B₁ extends X α where
bar : ∀ a, transform a = transform (transform a) → True
structure C₁ extends A₁ α, B₁ α
structure D₁ extends C₁ α where
foo := trivial
structure E₁ extends C₁ α where
bar _ _ := trivial
-- Always worked
example : D₁ α where
transform := id
bar := fun _ _ => trivial
-- Didn't work
example : E₁ α where
transform := id
foo := trivial
end Test2