lean4-htt/tests/elab/eqnsAtSimp3.lean
Garmelon 08eb78a5b2
chore: switch to new test/bench suite (#12590)
This PR sets up the new integrated test/bench suite. It then migrates
all benchmarks and some related tests to the new suite. There's also
some documentation and some linting.

For now, a lot of the old tests are left alone so this PR doesn't become
even larger than it already is. Eventually, all tests should be migrated
to the new suite though so there isn't a confusing mix of two systems.
2026-02-25 13:51:53 +00:00

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Text

def f (x y : Nat) : Nat :=
match x, y with
| 0, 0 => 1
| 0, y => y
| x+1, 5 => 2 * f x 0
| x+1, y => 2 * f x y
/--
trace: x y : Nat
h : y ≠ 5
⊢ ∃ z, 2 * f x y = 2 * z
-/
#guard_msgs in
theorem ex1 (x : Nat) (y : Nat) (h : y ≠ 5) : ∃ z, f (x+1) y = 2 * z := by
simp [f]
trace_state
apply Exists.intro
rfl
@[simp] def g (x y : Nat) : Nat :=
match x, y with
| 0, 0 => 1
| 0, y => y
| x+1, 5 => 2 * g x 0
| x+1, y => 2 * g x y
/--
trace: x y : Nat
h : y ≠ 5
⊢ ∃ z, 2 * g x y = 2 * z
-/
#guard_msgs in
theorem ex2 (x : Nat) (y : Nat) (h : y ≠ 5) : ∃ z, g (x+1) y = 2 * z := by
simp
trace_state
apply Exists.intro
rfl
/--
trace: x y : Nat
h : y = 5 → False
⊢ ∃ z, 2 * f x y = 2 * z
-/
#guard_msgs in
theorem ex3 (x : Nat) (y : Nat) (h : y = 5 → False) : ∃ z, f (x+1) y = 2 * z := by
simp [f]
trace_state
apply Exists.intro
rfl
@[simp] def f2 (x y z : Nat) : Nat :=
match x, y, z with
| 0, 0, 0 => 1
| 0, y, _ => y
| x+1, 5, 6 => 2 * f2 x 0 1
| x+1, y, z => 2 * f2 x y z
#check f2.eq_4
/--
trace: x y z : Nat
h : y = 5 → z = 6 → False
⊢ ∃ w, 2 * f2 x y z = 2 * w
-/
#guard_msgs in
theorem ex4 (x y z : Nat) (h : y = 5 → z = 6 → False) : ∃ w, f2 (x+1) y z = 2 * w := by
simp [f2]
trace_state
apply Exists.intro
rfl
theorem ex5 (x y z : Nat) (h1 : y ≠ 5) : ∃ w, f2 (x+1) y z = 2 * w := by
simp [f2, h1]
apply Exists.intro
rfl
theorem ex6 (x y z : Nat) (h2 : z ≠ 6) : ∃ w, f2 (x+1) y z = 2 * w := by
simp [f2, h2]
apply Exists.intro
rfl
@[simp] def f3 (x y z : Nat) : Nat :=
match x, y, z with
| 0, 0, 0 => 1
| 0, y, _ => y
| x+1, 5, 6 => 4 * f3 x 0 1
| x+1, 6, 4 => 3 * f3 x 0 1
| x+1, y, z => 2 * f3 x y z
#check f3.eq_5
theorem ex7 (x y z : Nat) (h2 : z ≠ 6) (h3 : y ≠ 6) : ∃ w, f3 (x+1) y z = 2 * w := by
simp [f3, h2, h3]
apply Exists.intro
rfl
theorem ex8 (x y z : Nat) (h2 : y = 5 → z = 6 → False) (h3 : y = 6 → z = 4 → False) : ∃ w, f3 (x+1) y z = 2 * w := by
simp [f3]
apply Exists.intro
rfl