64 lines
2.4 KiB
Text
64 lines
2.4 KiB
Text
universes u v
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theorem eqLitOfSize0 {α : Type u} (a : Array α) (hsz : a.size = 0) : a = #[] :=
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a.toArrayLitEq 0 hsz
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theorem eqLitOfSize1 {α : Type u} (a : Array α) (hsz : a.size = 1) : a = #[a.getLit 0 hsz (ofDecideEqTrue rfl)] :=
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a.toArrayLitEq 1 hsz
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theorem eqLitOfSize2 {α : Type u} (a : Array α) (hsz : a.size = 2) : a = #[a.getLit 0 hsz (ofDecideEqTrue rfl), a.getLit 1 hsz (ofDecideEqTrue rfl)] :=
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a.toArrayLitEq 2 hsz
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theorem eqLitOfSize3 {α : Type u} (a : Array α) (hsz : a.size = 3) :
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a = #[a.getLit 0 hsz (ofDecideEqTrue rfl), a.getLit 1 hsz (ofDecideEqTrue rfl), a.getLit 2 hsz (ofDecideEqTrue rfl)] :=
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a.toArrayLitEq 3 hsz
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/-
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Matcher for the following patterns
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```
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| #[] => _
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| #[a₁] => _
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| #[a₁, a₂, a₃] => _
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| a => _
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``` -/
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def matchArrayLit {α : Type u} (C : Array α → Sort v) (a : Array α)
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(h₁ : Unit → C #[])
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(h₂ : ∀ a₁, C #[a₁])
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(h₃ : ∀ a₁ a₂ a₃, C #[a₁, a₂, a₃])
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(h₄ : ∀ a, C a)
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: C a :=
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if h : a.size = 0 then
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@Eq.rec _ _ (fun x _ => C x) (h₁ ()) _ (a.toArrayLitEq 0 h).symm
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else if h : a.size = 1 then
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@Eq.rec _ _ (fun x _ => C x) (h₂ (a.getLit 0 h (ofDecideEqTrue rfl))) _ (a.toArrayLitEq 1 h).symm
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else if h : a.size = 3 then
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@Eq.rec _ _ (fun x _ => C x) (h₃ (a.getLit 0 h (ofDecideEqTrue rfl)) (a.getLit 1 h (ofDecideEqTrue rfl)) (a.getLit 2 h (ofDecideEqTrue rfl))) _ (a.toArrayLitEq 3 h).symm
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else
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h₄ a
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/- Equational lemmas that should be generated automatically. -/
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theorem matchArrayLit.eq1 {α : Type u} (C : Array α → Sort v)
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(h₁ : Unit → C #[])
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(h₂ : ∀ a₁, C #[a₁])
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(h₃ : ∀ a₁ a₂ a₃, C #[a₁, a₂, a₃])
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(h₄ : ∀ a, C a)
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: matchArrayLit C #[] h₁ h₂ h₃ h₄ = h₁ () :=
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rfl
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theorem matchArrayLit.eq2 {α : Type u} (C : Array α → Sort v)
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(h₁ : Unit → C #[])
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(h₂ : ∀ a₁, C #[a₁])
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(h₃ : ∀ a₁ a₂ a₃, C #[a₁, a₂, a₃])
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(h₄ : ∀ a, C a)
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(a₁ : α)
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: matchArrayLit C #[a₁] h₁ h₂ h₃ h₄ = h₂ a₁ :=
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rfl
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theorem matchArrayLit.eq3 {α : Type u} (C : Array α → Sort v)
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(h₁ : Unit → C #[])
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(h₂ : ∀ a₁, C #[a₁])
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(h₃ : ∀ a₁ a₂ a₃, C #[a₁, a₂, a₃])
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(h₄ : ∀ a, C a)
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(a₁ a₂ a₃ : α)
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: matchArrayLit C #[a₁, a₂, a₃] h₁ h₂ h₃ h₄ = h₃ a₁ a₂ a₃ :=
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rfl
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