lean4-htt/tests/lean/run/guessLex.lean
Joachim Breitner ffbea840bf
feat: WF.GuessLex: If there is only one plausible measure, use it (#2954)
If here is only one plausible measure, there is no point having the
`GuessLex` code see if it
is terminating, running all the tactics, only for the `MkFix` code then
run the tactics again.

So if there is only one plausible measure (non-mutual recursion with
only one varying
parameter), just use that measure.

Side benefit: If the function isn’t terminating, more detailed error
messages are shown
(failing proof goals), located at the recursive calls.
2023-11-27 22:41:40 +00:00

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/-!
This files tests Lean's ability to guess the right lexicographic order.
TODO: Once lean spits out the guessed order (probably guarded by an
option), turn this on and check the output.
When writing tests for GuesLex, keep in mind that it doesn't do anything
when there is only one plausible measure (one function, only one varying argument).
-/
def ackermann (n m : Nat) := match n, m with
| 0, m => m + 1
| .succ n, 0 => ackermann n 1
| .succ n, .succ m => ackermann n (ackermann (n + 1) m)
def ackermann2 (n m : Nat) := match n, m with
| m, 0 => m + 1
| 0, .succ n => ackermann2 1 n
| .succ m, .succ n => ackermann2 (ackermann2 m (n + 1)) n
def ackermannList (n m : List Unit) := match n, m with
| [], m => () :: m
| ()::n, [] => ackermannList n [()]
| ()::n, ()::m => ackermannList n (ackermannList (()::n) m)
def foo2 : Nat → Nat → Nat
| .succ n, 1 => foo2 n 1
| .succ n, 2 => foo2 (.succ n) 1
| n, 3 => foo2 (.succ n) 2
| .succ n, 4 => foo2 (if n > 10 then n else .succ n) 3
| n, 5 => foo2 (n - 1) 4
| n, .succ m => foo2 n m
| _, _ => 0
mutual
def even : Nat → Bool
| 0 => true
| .succ n => not (odd n)
def odd : Nat → Bool
| 0 => false
| .succ n => not (even n)
end
mutual
def evenWithFixed (m : String) : Nat → Bool
| 0 => true
| .succ n => not (oddWithFixed m n)
def oddWithFixed (m : String) : Nat → Bool
| 0 => false
| .succ n => not (evenWithFixed m n)
end
def ping (n : Nat) := pong n
where pong : Nat → Nat
| 0 => 0
| .succ n => ping n
def hasForbiddenArg (n : Nat) (_h : n = n) (m : Nat) : Nat :=
match n, m with
| 0, 0 => 0
| .succ m, n => hasForbiddenArg m rfl n
| m, .succ n => hasForbiddenArg (.succ m) rfl n
/-!
Example from “Finding Lexicographic Orders for Termination Proofs in
Isabelle/HOL” by Lukas Bulwahn, Alexander Krauss, and Tobias Nipkow,
10.1007/978-3-540-74591-4_5
-/
def blowup : Nat → Nat → Nat → Nat → Nat → Nat → Nat → Nat → Nat
| 0, 0, 0, 0, 0, 0, 0, 0 => 0
| 0, 0, 0, 0, 0, 0, 0, .succ i => .succ (blowup i i i i i i i i)
| 0, 0, 0, 0, 0, 0, .succ h, i => .succ (blowup h h h h h h h i)
| 0, 0, 0, 0, 0, .succ g, h, i => .succ (blowup g g g g g g h i)
| 0, 0, 0, 0, .succ f, g, h, i => .succ (blowup f f f f f g h i)
| 0, 0, 0, .succ e, f, g, h, i => .succ (blowup e e e e f g h i)
| 0, 0, .succ d, e, f, g, h, i => .succ (blowup d d d e f g h i)
| 0, .succ c, d, e, f, g, h, i => .succ (blowup c c d e f g h i)
| .succ b, c, d, e, f, g, h, i => .succ (blowup b c d e f g h i)
-- Lets try to confuse the lexicographic guessing function's
-- unpacking of packed n-ary arguments
def confuseLex1 : Nat → @PSigma Nat (fun _ => Nat) → Nat
| 0, _p => 0
| .succ n, ⟨x,y⟩ => confuseLex1 n ⟨x, .succ y⟩
def confuseLex2 : @PSigma Nat (fun _ => Nat) → Nat
| ⟨_,0⟩ => 0
| ⟨0,_⟩ => 0
| ⟨.succ y,.succ n⟩ => confuseLex2 ⟨y,n⟩
def dependent : (n : Nat) → (m : Fin n) → Nat
| 0, i => Fin.elim0 i
| .succ 0, 0 => 0
| .succ (.succ n), 0 => dependent (.succ n) ⟨n, n.lt_succ_self⟩
| .succ (.succ n), ⟨.succ m, h⟩ =>
dependent (.succ (.succ n)) ⟨m, Nat.lt_of_le_of_lt (Nat.le_succ _) h⟩
-- An example based on a real world problem, condensed by Leo
inductive Expr where
| add (a b : Expr)
| val (n : Nat)
mutual
def eval (a : Expr) : Nat :=
match a with
| .add x y => eval_add (x, y)
| .val n => n
def eval_add (a : Expr × Expr) : Nat :=
match a with
| (x, y) => eval x + eval y
end