lean4-htt/tests/lean/run/eqnsAtSimp3.lean
Joachim Breitner 0e49576fe4
feat: guard_msgs to treat trace messages separate (#8267)
This PR makes `#guard_msgs` to treat `trace` messages separate from
`info`, `warning` and `error`. It also introduce the ability to say
`#guard_msgs (pass info`, like `(drop info)` so far, and also adds
`(check info)` as the explicit form of `(info)`, for completeness.

Fixes #8266
2025-05-09 05:44:34 +00:00

101 lines
2.1 KiB
Text

def f (x y : Nat) : Nat :=
match x, y with
| 0, 0 => 1
| 0, y => y
| x+1, 5 => 2 * f x 0
| x+1, y => 2 * f x y
/--
trace: x y : Nat
h : y ≠ 5
⊢ ∃ z, 2 * f x y = 2 * z
-/
#guard_msgs in
theorem ex1 (x : Nat) (y : Nat) (h : y ≠ 5) : ∃ z, f (x+1) y = 2 * z := by
simp [f, h]
trace_state
apply Exists.intro
rfl
@[simp] def g (x y : Nat) : Nat :=
match x, y with
| 0, 0 => 1
| 0, y => y
| x+1, 5 => 2 * g x 0
| x+1, y => 2 * g x y
/--
trace: x y : Nat
h : y ≠ 5
⊢ ∃ z, 2 * g x y = 2 * z
-/
#guard_msgs in
theorem ex2 (x : Nat) (y : Nat) (h : y ≠ 5) : ∃ z, g (x+1) y = 2 * z := by
simp [h]
trace_state
apply Exists.intro
rfl
/--
trace: x y : Nat
h : y = 5 → False
⊢ ∃ z, 2 * f x y = 2 * z
-/
#guard_msgs in
theorem ex3 (x : Nat) (y : Nat) (h : y = 5 → False) : ∃ z, f (x+1) y = 2 * z := by
simp [f, h]
trace_state
apply Exists.intro
rfl
@[simp] def f2 (x y z : Nat) : Nat :=
match x, y, z with
| 0, 0, 0 => 1
| 0, y, z => y
| x+1, 5, 6 => 2 * f2 x 0 1
| x+1, y, z => 2 * f2 x y z
#check f2.eq_4
/--
trace: x y z : Nat
h : y = 5 → z = 6 → False
⊢ ∃ w, 2 * f2 x y z = 2 * w
-/
#guard_msgs in
theorem ex4 (x y z : Nat) (h : y = 5 → z = 6 → False) : ∃ w, f2 (x+1) y z = 2 * w := by
simp [f2, h]
trace_state
apply Exists.intro
rfl
theorem ex5 (x y z : Nat) (h1 : y ≠ 5) : ∃ w, f2 (x+1) y z = 2 * w := by
simp [f2, h1]
apply Exists.intro
rfl
theorem ex6 (x y z : Nat) (h2 : z ≠ 6) : ∃ w, f2 (x+1) y z = 2 * w := by
simp [f2, h2]
apply Exists.intro
rfl
@[simp] def f3 (x y z : Nat) : Nat :=
match x, y, z with
| 0, 0, 0 => 1
| 0, y, z => y
| x+1, 5, 6 => 4 * f3 x 0 1
| x+1, 6, 4 => 3 * f3 x 0 1
| x+1, y, z => 2 * f3 x y z
#check f3.eq_5
theorem ex7 (x y z : Nat) (h2 : z ≠ 6) (h3 : y ≠ 6) : ∃ w, f3 (x+1) y z = 2 * w := by
simp [f3, h2, h3]
apply Exists.intro
rfl
theorem ex8 (x y z : Nat) (h2 : y = 5 → z = 6 → False) (h3 : y = 6 → z = 4 → False) : ∃ w, f3 (x+1) y z = 2 * w := by
simp [f3, h2, h3]
apply Exists.intro
rfl