lean4-htt/tests/lean/run/wfirred.lean
Bhavik Mehta 43a9c73556
chore: fix typo and incorrect name in doc (#4404)
Fixes typo "reflexivitiy" to "reflexivity", and changes exact Eq.rfl to
exact rfl, since Eq.rfl does not exist.

(I got something confused wrt the bot message on #4367 and accidentally
closed that one, so making this one instead, which I think satisfies the
requirements it wanted.)

---------

Co-authored-by: Joachim Breitner <mail@joachim-breitner.de>
2024-06-23 09:06:50 +00:00

140 lines
2.4 KiB
Text

/-!
Tests that definitions by well-founded recursion are irreducible.
-/
def foo : Nat → Nat
| 0 => 0
| n+1 => foo n
termination_by n => n
/--
error: type mismatch
rfl
has type
foo 0 = foo 0 : Prop
but is expected to have type
foo 0 = 0 : Prop
-/
#guard_msgs in
example : foo 0 = 0 := rfl
/--
error: type mismatch
rfl
has type
foo (n + 1) = foo (n + 1) : Prop
but is expected to have type
foo (n + 1) = foo n : Prop
-/
#guard_msgs in
example : foo (n+1) = foo n := rfl
-- This succeeding is a bug or misfeature in the rfl tactic, using the kernel defeq check
#guard_msgs in
example : foo 0 = 0 := by rfl
-- It only works on closed terms:
/--
error: The rfl tactic failed. Possible reasons:
- The goal is not a reflexive relation (neither `=` nor a relation with a @[refl] lemma).
- The arguments of the relation are not equal.
Try using the reflexivity lemma for your relation explicitly, e.g. `exact Eq.refl _` or
`exact HEq.rfl` etc.
n : Nat
⊢ foo (n + 1) = foo n
-/
#guard_msgs in
example : foo (n+1) = foo n := by rfl
section Unsealed
unseal foo
example : foo 0 = 0 := rfl
example : foo 0 = 0 := by rfl
example : foo (n+1) = foo n := rfl
example : foo (n+1) = foo n := by rfl
end Unsealed
--should be sealed again here
/--
error: type mismatch
rfl
has type
foo 0 = foo 0 : Prop
but is expected to have type
foo 0 = 0 : Prop
-/
#guard_msgs in
example : foo 0 = 0 := rfl
def bar : Nat → Nat
| 0 => 0
| n+1 => bar n
termination_by n => n
-- Once unsealed, the full internals are visible. This allows one to prove, for example
/--
error: type mismatch
rfl
has type
foo = foo : Prop
but is expected to have type
foo = bar : Prop
-/
#guard_msgs in
example : foo = bar := rfl
unseal foo bar in
example : foo = bar := rfl
-- Attributes on the definition take precedence
@[semireducible] def baz : Nat → Nat
| 0 => 0
| n+1 => baz n
termination_by n => n
example : baz 0 = 0 := rfl
seal baz in
/--
error: type mismatch
rfl
has type
baz 0 = baz 0 : Prop
but is expected to have type
baz 0 = 0 : Prop
-/
#guard_msgs in
example : baz 0 = 0 := rfl
example : baz 0 = 0 := rfl
@[reducible] def quux : Nat → Nat
| 0 => 0
| n+1 => quux n
termination_by n => n
example : quux 0 = 0 := rfl
set_option allowUnsafeReducibility true in
seal quux in
/--
error: type mismatch
rfl
has type
quux 0 = quux 0 : Prop
but is expected to have type
quux 0 = 0 : Prop
-/
#guard_msgs in
example : quux 0 = 0 := rfl
example : quux 0 = 0 := rfl