lean4-htt/tests/lean/run/splitIssue.lean
Scott Morrison 3f548edcd7
chore: upstream (most of) Std.Data.Nat.Lemmas (#3391)
When updating Std, be careful that not every lemma has been upstreamed,
so we need to be careful to only delete things that have already been
declared.
2024-02-19 03:47:49 +00:00

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inductive ListSplit {α : Type u} : List α → Type u
| split l₁ l₂ : ListSplit (l₁ ++ l₂)
def splitList {α : Type _} : (l : List α) → ListSplit l
| [] => ListSplit.split [] []
| h :: t => ListSplit.split [h] t
def len : List α → Nat
| [] => 0
| a :: [] => 1
| l =>
match splitList l with
| ListSplit.split fst snd => len fst + len snd
termination_by l => l.length
decreasing_by
all_goals sorry
theorem len_nil : len ([] : List α) = 0 := by
simp [len]
-- The `simp [len]` above generated the following equation theorems for len
#check @len._eq_1
#check @len._eq_2
#check @len._eq_3 -- It is conditional, and may be tricky to use.
theorem len_1 (a : α) : len [a] = 1 := by
simp [len]
theorem len_2 (a b : α) (bs : List α) : len (a::b::bs) = 1 + len (b::bs) := by
conv => lhs; unfold len
-- The `unfold` tactic above generated the following theorem
#check @len._unfold
theorem len_cons (a : α) (as : List α) : len (a::as) = 1 + len as := by
cases as with
| nil => simp [len_1, len_nil]
| cons b bs => simp [len_2]
theorem listlen : ∀ l : List α, l.length = len l := by
intro l
induction l with
| nil => rfl
| cons h t ih =>
simp [List.length, len_cons, ih]
rw [Nat.add_comm]