lean4-htt/tests/lean/run/fib_wrec.lean
2017-03-09 18:41:19 -08:00

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open nat
definition fib.F (n : nat) : (Π (m : nat), m < n → nat) → nat :=
nat.cases_on n
(λ (f : Π (m : nat), m < 0 → nat), succ 0)
(λ (n₁ : nat), nat.cases_on n₁
(λ (f : Π (m : nat), m < (succ 0) → nat), succ 0)
(λ (n₂ : nat) (f : Π (m : nat), m < (succ (succ n₂)) → nat),
have l₁ : succ n₂ < succ (succ n₂), from lt.base (succ n₂),
have l₂ : n₂ < succ (succ n₂), from nat.lt_trans (lt.base n₂) l₁,
f (succ n₂) l₁ + f n₂ l₂))
definition fib (n : nat) :=
well_founded.fix lt_wf fib.F n
theorem fib.zero_eq : fib 0 = 1 :=
well_founded.fix_eq lt_wf fib.F 0
theorem fib.one_eq : fib 1 = 1 :=
well_founded.fix_eq lt_wf fib.F 1
theorem fib.succ_succ_eq (n : nat) : fib (succ (succ n)) = fib (succ n) + fib n :=
well_founded.fix_eq lt_wf fib.F (succ (succ n))
/-
The new elaborator never unfolds theorems.
Thus, the following examples are rejected by it.
The kernel would accept them.
TODO(Leo): add some mechanism for bypassing the elaborator.
example : fib 5 = 8 :=
rfl
example : fib 6 = 13 :=
rfl
-/
#print "------------"
#reduce fib 10
#eval fib 10